n^2-26n-50=0

Solution for n^2-26n-50=0 equation:

n^2-26n-50=0

a = 1; b = -26; c = -50;
Δ = b2-4ac
Δ = -262-4·1·(-50)
Δ = 876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{876}=\sqrt{4*219}=\sqrt{4}*\sqrt{219}=2\sqrt{219}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2\sqrt{219}}{2*1}=\frac{26-2\sqrt{219}}{2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2\sqrt{219}}{2*1}=\frac{26+2\sqrt{219}}{2}
$